tag:blogger.com,1999:blog-4284782026726334940.post8780179841786716068..comments2023-10-12T02:54:47.216-07:00Comments on Lenny Conundrum Answers: Lenny Conundrum - Round #424LennyC Solverhttp://www.blogger.com/profile/11602378112536054279noreply@blogger.comBlogger76125tag:blogger.com,1999:blog-4284782026726334940.post-6422168377163791592011-10-23T07:00:23.887-07:002011-10-23T07:00:23.887-07:00Its 67, my friend and I used autocad on this and t...Its 67, my friend and I used autocad on this and that cannot be wrong.Anonymousnoreply@blogger.comtag:blogger.com,1999:blog-4284782026726334940.post-72593823256803753502011-10-22T04:47:17.136-07:002011-10-22T04:47:17.136-07:00OH! Maybe the path is 1 meter wide PERPENDICULAR ...OH! Maybe the path is 1 meter wide PERPENDICULAR to the path. We were all using the idea that the path is 1 meter wide parallel to the sides of the garden. If you do the math that way, then instead of the path being 1 meter "wide", you have to use a right triangle with arctan(40/55) and one leg being one meter wide, so you'd have to figure the area of the path using a width of 1/cos(arctan(40/55))=1.23649. Which means the path should have an area of...<br />49.46?<br /><br />Somebody want to double-check my math? I thought I had this cracked, but apparently not.Rowannoreply@blogger.comtag:blogger.com,1999:blog-4284782026726334940.post-88558221325883481772011-10-20T00:32:10.978-07:002011-10-20T00:32:10.978-07:0064?!?!?!? Are they insane?! How did they come up w...64?!?!?!? Are they insane?! How did they come up with that?!Anonymousnoreply@blogger.comtag:blogger.com,1999:blog-4284782026726334940.post-58204476052311631162011-10-19T20:06:52.085-07:002011-10-19T20:06:52.085-07:00It's a case of sometimes people screw the heck...It's a case of sometimes people screw the heck up.Anonymousnoreply@blogger.comtag:blogger.com,1999:blog-4284782026726334940.post-43250434637157245592011-10-19T17:55:29.789-07:002011-10-19T17:55:29.789-07:00what the huckwhat the huckAnonymousnoreply@blogger.comtag:blogger.com,1999:blog-4284782026726334940.post-81811827228998090042011-10-19T16:58:46.396-07:002011-10-19T16:58:46.396-07:00Seriously... is this just a case of "life isn...Seriously... is this just a case of "life isn't fair?"Anonymousnoreply@blogger.comtag:blogger.com,1999:blog-4284782026726334940.post-57125195327792451432011-10-19T14:33:16.845-07:002011-10-19T14:33:16.845-07:00TNT is assuredly wrong. The answer is DEFINITELY 6...TNT is assuredly wrong. The answer is DEFINITELY 67 (200/3, or 66.66666...). Some of the answers above have complete explanations for it being 67.<br /><br />How do we tell them they're wrong?Anonymousnoreply@blogger.comtag:blogger.com,1999:blog-4284782026726334940.post-50401933538450643992011-10-19T14:27:03.506-07:002011-10-19T14:27:03.506-07:00TNT says 64???TNT says 64???Anonymousnoreply@blogger.comtag:blogger.com,1999:blog-4284782026726334940.post-59853240433119155752011-10-19T06:17:12.919-07:002011-10-19T06:17:12.919-07:00Okay it's either 68 or 67 or 40. 68/67 I gathe...Okay it's either 68 or 67 or 40. 68/67 I gathered from using pythagoras theorem and then multiply by the width (1) which left 68. However, I realised that the triangle is NOT actually 55 long... the path is 1 yard wide so it is actually 54. <br /><br />So, I got 67 that way.<br /><br />Then I realised that the path is not a rectangle so you can't just use the worked out sides and times it by 1.. (can you?)<br /><br />Sooo what I did is worked out the added areas of both triangles 2( 1/2 * 40 * 54 )and then that answer subtracted from the total area of the entire garden. So, what is left is the area of the path.<br />However, neopets say 'round to the nearest number' so yeah...Anonymousnoreply@blogger.comtag:blogger.com,1999:blog-4284782026726334940.post-60916327059431705572011-10-18T22:37:31.904-07:002011-10-18T22:37:31.904-07:0040^2 + (55-X)^2 = 40X^2
^ I have no idea what you...40^2 + (55-X)^2 = 40X^2<br /><br />^ I have no idea what you are calculating with this? 40x would be the area of the path, not the length of the hypotenuse.Anonymousnoreply@blogger.comtag:blogger.com,1999:blog-4284782026726334940.post-84231773007186057162011-10-17T13:53:32.313-07:002011-10-17T13:53:32.313-07:00Answer is 67 or (66.6666666)
Formulas Needed: Pyt...Answer is 67 or (66.6666666)<br /><br />Formulas Needed: Pythagoras and area of a parallelogram <br /><br />Lets call the little section from the side 55 as "X" an unknown value<br /><br />40^2 + (55-X)^2 = 40X^2 (40x because parallelogram is base x Height, we know the height of 40 but no base.) That = X^2 - 110X + 4625 = 1600X^2<br /><br />Rearrange by taking them all on the left across = 1599X^2 +100X - 4625 = 0<br /><br />Now the Quadratic Formula <br /><br />-B ± (Square root)/b^2-(4AC)<br />---------------------------<br /> (2 x A)<br /><br />Therefore: = <br /> ______________________<br />-110x ± √110^2 - (4x1599x-4625) <br />--------------------------------- = 5/3 or 1.67<br /> (2 x 1599)<br /><br />x= 1.6666666 so (55-x) = (55 - 1.66666) = 53.333<br /><br />Last but not least pythagoras as 1 yard would not affect the area from the hypotenuse of the triangle= 53.333^2 + 40^2 = 4444.44444 then square root 4444.4444 = 66.66666666 rounder up = 67!!!<br /><br />Peace ^^Anonymousnoreply@blogger.comtag:blogger.com,1999:blog-4284782026726334940.post-43075910323150269172011-10-17T13:44:42.273-07:002011-10-17T13:44:42.273-07:00I still go with my answer of 57 (56.5)
I hope I w...I still go with my answer of 57 (56.5)<br /><br />I hope I win a bigger loot this round. I was the first one to reply to this thread with 57 as an answer. Lol.Anonymousnoreply@blogger.comtag:blogger.com,1999:blog-4284782026726334940.post-30607849768039808432011-10-16T22:41:50.545-07:002011-10-16T22:41:50.545-07:00Otherwise correct, but the base of the triangle IS...Otherwise correct, but the base of the triangle IS NOT 54!<br /><br />http://tinypic.com/r/2zrdc1e/7<br /><br />As you can see in this picture the red line is the mentioned one yard. The blue line is therefore the squareroot of two. Which makes the base of the triangle 53.5858 yards.<br /><br />40*53.5858=2143.432<br />2200-2143.432=56.568=57Anonymousnoreply@blogger.comtag:blogger.com,1999:blog-4284782026726334940.post-29576395064144396922011-10-16T21:06:00.223-07:002011-10-16T21:06:00.223-07:00Let me answer this for you. The area of the entire...Let me answer this for you. The area of the entire rectangle is 2200. (55x40=2200)<br /><br />To figure out the area of the path, you must figure out the area of both triangles. Given that the path is one yard wide, the base and height of both triangles is 54 and 40... so you just need to multiply 54 by 40 and subtract that from 2200. (yes the area of a triangle is 1/2(b*h) but both triangles are the same size so its unnecessary to divide by half and add them together) <br /><br />The answer is 40sq. yards. 2200-2160=40Anonymousnoreply@blogger.comtag:blogger.com,1999:blog-4284782026726334940.post-70210178326360474312011-10-16T20:57:49.025-07:002011-10-16T20:57:49.025-07:00You guys are making this WAY MORE COMPLICATED than...You guys are making this WAY MORE COMPLICATED than it actually is...Anonymousnoreply@blogger.comtag:blogger.com,1999:blog-4284782026726334940.post-90404855867024905322011-10-16T15:20:43.715-07:002011-10-16T15:20:43.715-07:00YOU GUYS ARE IDIOTS!!!!! First of all, i think the...YOU GUYS ARE IDIOTS!!!!! First of all, i think the 40 theory sounds most logical to me and also it says to enter your number in SQUARE YARDS therefore the answer should be 40 sq. yds.Anonymousnoreply@blogger.comtag:blogger.com,1999:blog-4284782026726334940.post-87199638403406224592011-10-15T19:26:35.290-07:002011-10-15T19:26:35.290-07:0040 sounds plausible in hindsight, but it is not. T...40 sounds plausible in hindsight, but it is not. Though 57 sounds odd, it has a better chance of winning than 40. Oh well, hoping my early submission of 67 does the trick.Anonymousnoreply@blogger.comtag:blogger.com,1999:blog-4284782026726334940.post-19134363134597466572011-10-14T09:51:34.300-07:002011-10-14T09:51:34.300-07:00There is no way it even could be 40. The path is c...There is no way it even could be 40. The path is clearly longer than the 40 yard long side. If the path was 40 square yards, it would have to be 40 yards long as it is stated that it's 1 yard wide.Anonymousnoreply@blogger.comtag:blogger.com,1999:blog-4284782026726334940.post-43545502847466231952011-10-14T01:04:16.982-07:002011-10-14T01:04:16.982-07:00Pythagoras is not needed for this exceedingly simp...Pythagoras is not needed for this exceedingly simple problem. You can either tae the entire rectangle and substract the two triangles or look at the path as the paralellogram it is. Both methods will yield you 40, the correct answer.Anonymousnoreply@blogger.comtag:blogger.com,1999:blog-4284782026726334940.post-48757976093926872462011-10-13T21:16:09.436-07:002011-10-13T21:16:09.436-07:0040,67,6840,67,68Anonymousnoreply@blogger.comtag:blogger.com,1999:blog-4284782026726334940.post-84841012818519559942011-10-13T20:56:29.373-07:002011-10-13T20:56:29.373-07:00I will be laughing my ass off, when they tell you ...I will be laughing my ass off, when they tell you it's 57. Or 56 if TNT screws up the rounding up again.Anonymousnoreply@blogger.comtag:blogger.com,1999:blog-4284782026726334940.post-24983440783053921012011-10-13T11:49:47.266-07:002011-10-13T11:49:47.266-07:00I know simple math and I am pretty sure it's 5...I know simple math and I am pretty sure it's 54.Anonymousnoreply@blogger.comtag:blogger.com,1999:blog-4284782026726334940.post-980023399635830072011-10-13T11:19:40.173-07:002011-10-13T11:19:40.173-07:00Learn simple maths and then come online to complai...Learn simple maths and then come online to complain! the answer is 57. You saw it proved above.Anonymousnoreply@blogger.comtag:blogger.com,1999:blog-4284782026726334940.post-86843074185691387612011-10-13T10:58:10.785-07:002011-10-13T10:58:10.785-07:00Finally I mean, I thought no one would get it righ...Finally I mean, I thought no one would get it right like me xDAnonymousnoreply@blogger.comtag:blogger.com,1999:blog-4284782026726334940.post-3395792428689684352011-10-13T10:57:16.585-07:002011-10-13T10:57:16.585-07:00FINALLY!!
Yep, the answer is 53,6585 = 54!FINALLY!!<br /><br />Yep, the answer is 53,6585 = 54!Anonymousnoreply@blogger.com